By Sigurdur Helgason (auth.)
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Extra resources for The Radon Transform
R whence S(ep) = S(ep) = O. A (lS) Proof. 1, The other relation is proved in the same manner. 6) for distributions. 4. supp Ißt TE &'
Is a function pn. 4. Let A be!!! defined cf = (Ai? ' f ~ E (37). n) I Then 26 Ch. I where as before c = (-471) Proof. ~ r(Z) ::r:- . r(Z) By the inversion fomula for the Fourier transfonn and by (4) (271)-nJdw~ (~e-iSPf(w,p)dP)eis(X,w)sn-lds f(x) Sn-1 which Yle -00 wri te as f(x) = (271) /\ Using f(-w,-p) f(x) (38) 0 = -nln-lF(w,x)dw = (271) -nfSn-l 1 (~~(w,x) ,.. f(w,p) + F(-w,x)) dw this gives the formula = ~(271)-nfn_~foolsln-leiS(X,W)dsf:-iSP f(w,p)dp S _00 _00 If n is odd the absolute value on s can be dropped.
Denoting closure, and I the identity. If Tg Proof. Dg0 2 = = (g,g) (Tg,g) = g then since = (g,T*g) the inequalities are equal. ßg - T*g112 so T*g = g. ts 11 T*II = 11 TU ~ 1 we have ~ ßgn ßT*gll ~ ngn 2 so all terms in Hence = ßgll 2 - (g,T*g) - (T*g,g) + nT*gll2 = 0 I - T and is equivalent to I - T* have the sarre 001 space.
The Radon Transform by Sigurdur Helgason (auth.)